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Thread: Problem with inner - left join - I need some clue

  1. #1
    Join Date
    Apr 2005
    Location
    Brazil
    Posts
    9

    Unhappy Problem with inner - left join - I need some clue

    Hello Guys,
    I really need your help,

    I have two tables

    FIRST TABLE: CADPAL
    Fields:

    CP_COD (number)
    CP_DESCRIPTION (TEXTO 50)

    SECOND TABLE: CTRPL

    CTP_CODPAL
    CTP_CODUSO
    CTP_LANGUAGE

    I need to retrieve all the records from CADPAL that aren't in the CTRPL, I did something like that:

    SELECT CP_CODIGO, CP_DESCRICPTION FROM CADPAL
    WHERE CP_CODIGO NOT IN (SELECT CTP_CODPAL FROM CTRPL
    WHERE CTP_CODUSO=1 AND CTP_LANGUAGE='US')

    The problem is that it works very fine in access, but when I use this SELECT in my application, it gets very slow.

    Is there any way to do that with join? I tried but it didn't work

    The database is available to download

    Thanks
    Alexandre


    A friend Answered with this example

    SELECT CP_CODIGO, CP_DESCRICPTION
    FROM CADPAL
    LEFT JOIN CTRPL
    ON (CP_CODIGO = CTP_CODPAL AND CTP_CODUSO=1)
    WHERE CTP_CODPAL IS NULL

    I tried and everything went fine with access 2003, but it doesn't worked with my version access 2000. I tried several
    other ways, but nothing.

    Someone could help me

    Thanks

  2. #2
    Join Date
    Feb 2003
    Posts
    1,048
    It should work with Access 2000. The query is correct. You did leave out the CTP_LANGUAGE='US'.

  3. #3
    Join Date
    Apr 2005
    Location
    Brazil
    Posts
    9

    Hello

    Hello Friend
    Unfortunately I didn't work in my access 2000. Here in the company it worked very fine, the version here is access 2003. Strange, no? If you can send me your email so that we can talk faster.

    What about leaving the CTP_LANGUAGE='US', I can't, because I need it to make the filter too.

    Thanks in advance for you help

  4. #4
    Join Date
    Feb 2003
    Posts
    1,048
    Sorry, I don't do direct email support.

    I think what may be happening is that the inclusion of "CTP_CODUSO=1" is forcing it into an inner join. It can't have a value in CTP_CODUSO and CTP_CODPAL be null both.

  5. #5
    Join Date
    Apr 2005
    Location
    Brazil
    Posts
    9

    Thumbs up Thanks very much

    Ok, I am gonna try today. Thanks once again

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