PHP ')' error. line 4

[tymlls05]

It says I have an error at line 4. Sorry to say thats all I know. Anyone know how i can fix or clean up this script?

<?php $dbconnection = @mysql_connect(localhost, admin, password);

if (!$dbconnection) {
  echo( "<p>Unable to connect to the " . "database server at this time.</p>" );
  exit();
}

if (! @mysql_select_db("database") ) {
  echo( "<p>Unable to locate the joke " .
        "database at this time.</p>" );
  exit();
}
$user=$_POST['name'];

if (!$_POST['name']) {
  echo( "<p>please submit form" );
}else{
$sql = "CREATE TABLE $user (
         ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
         $user TEXT,
       )";
if ( @mysql_query($sql) ) {
  echo("<p>".$user." table successfully created!</p>");
} else {
  echo("<p>Error creating ".$user." table: " . mysql_error() . "</p>");
}
}
?>

<form method="post" action="newsite.php">
Enter your name: <input type="text" name="name">
<input type="submit" value="done!">
</form>

If input field "name" is blank. i want it to do nothing. if it has input in the field i want it to create a table in the database called whatever the input is.

Thanks,
Tyler