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Adding Next Appointment Date
Hi I'm dave and I'm new to the forum, SQL and SSRS. Thanks in advance for your assistance and patience.
I have a recall report that produces letters for every patient who needs to return to the office on a certain date based on their recall plan (a plan that determines when they should return based on their condition). I have another table that stores all appointments for each patients (past and present). Appointments in the recall_plans table are auto-generated whereas appointments in the appointments table where created manually. The recall plan report is not checked if a person calls in to make an appointment so often the same appointment is represented in both tables resulting in duplicate reminder letters being sent out.
I need to do two things:
(I know my approach is not necessarily resolving the business problem but this is what I am tasked with)
- I need to produce a list showing the next appointment for each patient but only if it is in the future.
- I need to add a column to the first report showing each patient’s next appointment so someone can manually identify that duplicate letters would go out for specific patients and intervene accordingly.
Recall Report Query:
SELECT description as [Plan Name],
per.first_name + ' ' + per.last_name as [Patient],
substring (plan_start_date, 5,2) + '-' +
substring (plan_start_date, 7,2) + '-' +
substring (plan_start_date, 1,4) as [Plan Start Date],
substring (nr.expected_return_date, 5,2) + '-' +
substring (nr.expected_return_date, 7,2) + '-' +
substring (nr.expected_return_date, 1,4) as [Expected Return Date]
FROM recall_plan_mstr rp,
patient_recall_plans nr,
patient pt,
person per
WHERE rp.practice_id = nr.practice_id
and rp.recall_plan_id = nr.recall_plan_id
and nr.practice_id = pt.practice_id
and nr.person_id = pt.person_id
and per.person_id = pt.person_id
and (active_plan_ind = 'Y')
and rp.practice_id = '0025'
Recall Report Results:
PLAN NAME PATIENT START RETURN
OFFICE VISIT W/ DR Charles Span 04-18-2011 12-15-2011
LIPID PANEL Ronald Chap 04-11-2011 06-28-2011
OFFICE VISIT W/ DR Ronald Chap 04-11-2011 04-21-2011
OFFICE VISIT W/ DR Will Thor 03-31-2011 02-01-2012
PACEMAKER CHECK Sylvia Berkly 05-03-2011 08-03-2011
OFFICE VISIT W/ DR Tim Cayle 04-13-2011 09-26-2011
OFFICE VISIT W/ DR Caferana Mercade 04-11-2011 10-08-2011
OFFICE VISIT W/ DR Susanna Calter 05-10-2011 05-07-2012
ICD CHECK Jim Southern 04-14-2011 07-13-2011
STRESS ECHO Don Cobey 04-28-2011 06-07-2010
Appointments Query:
select person_id, appt_date
from appointments
where person_id is not null
group by person_id, appt_date
order by person_id, appt_date desc
Appointments Results:
073C8F83-CE15-4192-8E12-00006CB5A433 20091228
073C8F83-CE15-4192-8E12-00006CB5A433 20090510
073C8F83-CE15-4192-8E12-00006CB5A433 20090301
073C8F83-CE15-4192-8E12-00006CB5A433 20081006
378A281C-FAE7-43DF-BC03-00006E386680 20110509
378A281C-FAE7-43DF-BC03-00006E386680 20110217
378A281C-FAE7-43DF-BC03-00006E386680 20110124
378A281C-FAE7-43DF-BC03-00006E386680 20110111
378A281C-FAE7-43DF-BC03-00006E386680 20101207
816D4D31-3C99-4762-878D-000097883B73 20110316
816D4D31-3C99-4762-878D-000097883B73 20101216
Questions:
- How can I produce a list from the appointments table that results with one patient per row with only the latest appointment that is in the future? Do I need to write a cursor for that?
- How can I comingle this list into my recall report so it has a column to the right of return column that displays the patient’s next appointment date (future only)? Both tables have a person number GUID.
I hope I've adequately explained and provided enough information. If any additional information is needed please don’t hesitate to ask.
Thanks,
dave
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INSERT INTO #temp
SELECT person_id, appt_dt
FROM recall
WHERE appt_dt > getdate()
UNION
SELECT person_id, appt_dt
FROM appointment
WHERE appt_dt > getdate()
SELECT person_id, min(appt_dt)
FROM #temp
GROUP BY person_id
this would give you the next appointment for a person. Not super efficient, but it would work.
PS I think you need to fix the logic to get it to work correctly.
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