(MDX). Count 2 Dimensions in a Cube

Hi everyone.
suppose that i have 3 dimensions as.

ProductModel and Color
and SalesFact table.

i want to find the distinct count of ProductModel+Color.
i mean.
Year/ProductModel/Color/Sales
---------------
2006/010101 /White /1.0
2006/010101 /Black /2.0
2007/010101 /White /1.0

2006/010102 /White /1.0

2007/010102 /Black /3.0
2007/010103 /White /2.0

i am trying to add CalculatedMember in AS2000.
i can easily count ProductModel with.

Code:

---

iif(filter(descendants([ProductModel ],[ProductModel ].[Model Id]),[Measures].[Sales]<>0).count=0,
null,filter(descendants([ProductModel ],[ProductModel ].[Model Id]),[Measures].[Sales]<>0).count)

---

and i can get. By year
2006 - 010101 - 2
2007 - 010101 - 1
2006 - 010102 - 1
2007 - 010102 - 1
2007 - 010103 - 1

But i want to get count of ProductModel+Color
i mean.
i want see.
Year/ ModelCount/Model+colorCount

2006 - 2 - 3
2007 - 2 - 3

it means
2006 - 2(010101&010102) - 3 (010101White&010101Black&010102White)

i hope someone understand my question...

i just want to add second Dimension to this member formula query.
i wat to add [Colors].[Color ID] to this query.

filter(descendants([ProductModel ],[ProductModel ].[Model Id]),[Measures].[Sales]<>0).count)

Sortly;
i want distinct count of two dimensions :(((

ok. i found it.
no problem:o

NonEmptyCrossJoin ({[Measures].[Miktar]},
{Descendants ([Stoklar].CurrentMember, [Stoklar].[Model Id])},
{Descendants ([Renkler].CurrentMember, [Renkler].[Renk ID])}
).Count

What you got was a count of items returned via the crossjoin - which happened to juxtapose three dims (two dims and a measure, in 2k parlance) ...

Great to hear it was what you wanted ...

Keep us posted on your progress!

Bill